generated from mwc/lab_encryption
ebec786840
because I could actually test what was happening instead of just guessing. It made it easier to see how encryption and decryption work step by step, and I could quickly fix mistakes when something didn’t work. I had trouble finding the secret word at first because I was only getting numbers when I calculated the shifts. I couldn’t turn that into a readable word, so I used the secret word provided by the professor instead. Then I used that word in PolyCipher to decrypt the message and check that it worked.
39 lines
893 B
Markdown
39 lines
893 B
Markdown
# Encryption lab answers
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## Checkpoint 1
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0. `secrets/secret0.txt` is encrypted using a Caesar Cipher. What is
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its secret number?
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The number is 78.
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1. `secrets/secret1.txt` is encrypted using a Caesar Cipher. What is
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its secret number?
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The number is 1.
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2. `secrets/secret2.txt` is encrypted using a Caesar Cipher. What is
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its secret number?
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The number is 44.
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3. `secrets/secret3.txt` is encrypted using a Caesar Cipher. What is
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its secret number?
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The number is 59.
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4. `secrets/secret4.txt` is encrypted using a Caesar Cipher. What is
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its secret number?
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The number is 32.
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## Checkpoint 2
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5. What is the polyalphabetic secret word?
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The secret word is "PYTHON".
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6. Decrypt this message, which was encrypted using the same secret word:
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"EbZhdaV[h^bTpchhQnhig]X[VmhhRP]ftXVnRfjVY]fgtO_X]("
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The decrypt message is "The treasure is a worthless ball of aluminum foil." |