# Tic Tac Toe Lab Assessment

Everything's done--nice work!

## Checkpoint 1
Looks good.

## Checkpoint 2
This works! It probably felt a bit tedious. If I were trying to do this 
elegantly, I'd probably start by separating the data from the algorithm. 
Then, there are a number of python builtin functions and idioms which 
I'd reach for:

```
combos = [
    [0, 1, 2],
    [3, 4, 5],
    ...
]
is_symbol = lambda index: state['board'][index] == symbol
return any(all(map(is_symbol, combo)) for combo in combos)
```

Happy to explain what's going on here if you have trouble figuring it out :)

## Checkpoint 3
Looks good.