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Chris Proctor 2024-03-06 12:14:51 -05:00
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# Tic Tac Toe Lab Assessment
Everything's done--nice work!
## Checkpoint 1
Looks good.
## Checkpoint 2
This works! It probably felt a bit tedious. If I were trying to do this
elegantly, I'd probably start by separating the data from the algorithm.
Then, there are a number of python builtin functions and idioms which
I'd reach for:
```
combos = [
[0, 1, 2],
[3, 4, 5],
...
]
is_symbol = lambda index: state['board'][index] == symbol
return any(all(map(is_symbol, combo)) for combo in combos)
```
Happy to explain what's going on here if you have trouble figuring it out :)
## Checkpoint 3
Looks good.