Checkpoint 1: I finished planning.md

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Cory Dean Chung 2023-08-16 00:41:38 -04:00
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@ -38,18 +38,57 @@ return digit_names[number]
If the integer is under 10, then use the procedure described above.
Otherwise, ... (this is where you take over!)
## Integers under 100
We can again make a list of digit names:
```
digit_names = [
"zero", "one", "two", "three", "four",
"five", "six", "seven", "eight", "nine",
"ten", "eleven", "twelve", "thirteen",
"fourteen", "fifteen", "sixteen",
"seventeen", "eighteen", "nineteen"
]
return digit_names[number]
```
## Integers under 100
If the integer is under 20, then use the procedure described above.
Otherwise,
First, create a list of tens digit strings:
```
tens_names = [
"twenty", "thirty", "forty", "fifty",
"sixty", "seventy", "eighty", "ninety"
]
```
Second, determine the leading digit, using integer division by 10, and the ones digit using mod 10 and look up the correct names.
return tens_names[number / 10 - 2] + digit_names[number % 10]
## Integers under 1000
If the integer is under 100, then use the procedure described above. We'll call that procedure tens_number().
Otherwise,
First, create a list of hundreds digit srings:
```
hundreds_names = [
"one hundred", "two hundred", "three hundred",
"four hundred", "five hundred", "six hundred",
"seven hundred", "eight hundred", "nine hundred"
]
```
Second determine the hundreds digit using integer division by one hundred, the tens digit by finding the number mod 100 and applying tens_number(), and the ones digit by finding the number mod 10.
return hundreds_name[number / 100] + tens_number(number % 100) + digit_names[number % 10]
## Integers under 1000000
If the integer is under 1000, then use the procedure described above. We'll call that procedure hundreds_name().
return hundreds_name(number / 1000) + "thousand" + hundreds_name(number % 1000)
## Negative integers down to -1 million
We won't deal with negative integers in this problem set,
but how would you deal with a negative integer, using the
functions above?
If the number is positive, use the above method.
Otherwise, return "negative " + number_words(-1 * number)